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Python程序：計(jì)算等差數(shù)列和

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寫一個(gè) Python 程序，用一個(gè)實(shí)際例子求算術(shù)級(jí)數(shù)(A.P .級(jí)數(shù))的和。

Python 自動(dòng)編程系列

算術(shù)數(shù)列是一個(gè)術(shù)語序列，其中下一個(gè)項(xiàng)目是通過將一個(gè)共同的差異加到上一個(gè)項(xiàng)目上而獲得的?；蛘?A.P .級(jí)數(shù)是任意兩個(gè)連續(xù)數(shù)的差總是相同的一系列數(shù)。這種差異稱為共同差異。

在計(jì)算等差數(shù)列的數(shù)學(xué)中數(shù)列的和:Sn = n/2(2a+(n–1)d) 數(shù)列的 Tn 項(xiàng):Tn = a+(n–1)d

尋找等差數(shù)列和的 Python 程序示例

這個(gè) Python 程序允許用戶輸入第一個(gè)值、一個(gè)系列中的項(xiàng)目總數(shù)以及共同的區(qū)別。接下來，Python 找到算術(shù)級(jí)數(shù)的和。

# Python Program to find Sum of Arithmetic Progression Series

a = int(input("Please Enter First Number of an A.P Series: : "))
n = int(input("Please Enter the Total Numbers in this A.P Series: : "))
d = int(input("Please Enter the Common Difference : "))

total = (n * (2 * a + (n - 1) * d)) / 2
tn = a + (n - 1) * d

print("\nThe Sum of Arithmetic Progression Series = " , total)
print("The tn Term of Arithmetic Progression Series = " , tn)

計(jì)算等差數(shù)列和的 Python 程序示例 2

這個(gè) Python 的 A.P 程序的和同上。這里我們用 While Loop 顯示 A.P 系列，可選。

# Python Program to find Sum of Arithmetic Progression Series

a = int(input("Please Enter First Number of an A.P Series: : "))
n = int(input("Please Enter the Total Numbers in this A.P Series: : "))
d = int(input("Please Enter the Common Difference : "))

total = (n * (2 * a + (n - 1) * d)) / 2
tn = a + (n - 1) * d
i = a
print("\nThe tn Term of Arithmetic Progression Series = " , tn)
print("The Sum of Arithmetic Progression Series : ")
while(i <= tn):
    if(i != tn):
        print("%d + " %i, end = " ")
    else:
        print("%d = %d" %(i, total))
    i = i + d

算術(shù)級(jí)數(shù)和輸出

Please Enter First Number of an A.P Series: : 2
Please Enter the Total Numbers in this A.P Series: : 6
Please Enter the Common Difference : 4

The tn Term of Arithmetic Progression Series =  22
The Sum of Arithmetic Progression Series : 
2 +  6 +  10 +  14 +  18 +  22 = 72

不用數(shù)學(xué)公式計(jì)算等差數(shù)列和的 Python 程序

在這個(gè) Python 程序中，我們沒有使用任何數(shù)學(xué)公式。

# Python Program to find Sum of Arithmetic Progression Series

a = int(input("Please Enter First Number of an A.P Series: : "))
n = int(input("Please Enter the Total Numbers in this A.P Series: : "))
d = int(input("Please Enter the Common Difference : "))

total = 0
value = a
print("Arithmetic Progression Series : ", end = " ")
for i in range(n):
    print("%d + " %value, end = " ")
    total = total + value
    value = value + d

print("\nThe Sum of Arithmetic Progression Series upto %d = %d " %(n, total))

Python 算術(shù)級(jí)數(shù)求和輸出

Please Enter First Number of an A.P Series: : 1
Please Enter the Total Numbers in this A.P Series: : 4
Please Enter the Common Difference : 5
Arithmetic Progression Series :  1 +  6 +  11 +  16 +  
The Sum of Arithmetic Progression Series upto 4 = 34

用函數(shù)計(jì)算等差數(shù)列和的 Python 程序

這個(gè) Python 算術(shù)級(jí)數(shù)和與第一個(gè)例子相同。但是，我們使用函數(shù)來分離邏輯。

# Python Program to find Sum of Arithmetic Progression Series

def sumofAP(a, n, d):
    total = (n * (2 * a + (n - 1) * d)) / 2
    return total

a = int(input("Please Enter First Number of an A.P Series: : "))
n = int(input("Please Enter the Total Numbers in this A.P Series: : "))
d = int(input("Please Enter the Common Difference : "))

total = sumofAP(a, n, d)
print("\nThe Sum of Arithmetic Progression Series = " , total)